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> Resolucion de Guia de Inecuaciones
deixo
mensaje May 18 2008, 11:27 AM
Publicado: #1


Dios Matemático Supremo


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A pedido de Krizalid, Resolvamos Uno por uno los ejercicios de esta guía. guía de Inecuaciones




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.


Psdt. Jajja, Igual terrible metío, si yo soy de la federico...jaja

Mensaje modificado por deixo el May 18 2008, 12:25 PM
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mensaje May 18 2008, 11:46 AM
Publicado: #2


Dios Matemático Supremo


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Mensaje modificado por deixo el May 18 2008, 11:47 AM
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mensaje May 18 2008, 12:02 PM
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Dios Matemático Supremo


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mensaje May 18 2008, 12:07 PM
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mensaje May 18 2008, 12:13 PM
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mensaje May 18 2008, 12:17 PM
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mensaje May 18 2008, 12:23 PM
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7)

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Mensaje modificado por deixo el May 18 2008, 12:39 PM
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mensaje May 18 2008, 12:38 PM
Publicado: #8


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TEX: % MathType!MTEF!2!1!+-<br />% feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn<br />% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr<br />% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9<br />% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x<br />% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaacaaI4a<br />% GaaiykaaqaaaqaaiaaykW7caaMc8UaaGPaVlaaykW7caaMc8UaaGPa<br />% VlaadMhacaGGOaGaamyEaiabgUcaRiaaiAdacaGGPaGaeyOpa4JaaG<br />% OnaaqaaiaadMhadaahaaWcbeqaaiaaikdaaaGccqGHRaWkcaaI2aGa<br />% amyEaiabgkHiTiaaiAdacqGH+aGpcaaIWaaabaaabaGaam4uaiaadg<br />% gacaWGJbGaamyyaiaad6gacaWGKbGaam4BaiaaygW7caaMc8UaamOC<br />% aiaadggacaWGPbGaam4yaiaadwgacaWGZbGaaiOoaaqaaaqaamaala<br />% aabaGaeyOeI0IaaGOnaiabgglaXoaakaaabaGaaG4maiaaiAdacqGH<br />% sislcaaI0aGaaiikaiabgkHiTiaaiAdacqGHflY1caaIXaaaleqaaO<br />% GaaiykaaqaaiaaikdaaaGaeyypa0ZaaSaaaeaacqGHsislcaaI2aGa<br />% eyySae7aaOaaaeaacaaI2aGaaGimaaWcbeaaaOqaaiaaikdaaaGaey<br />% ypa0ZaaSaaaeaaceaIYaGbaybacaGGOaGaeyOeI0IaaG4maiabggla<br />% XoaakaaabaGaaGymaiaaiwdaaSqabaGccaGGPaaabaGabGOmayaawa<br />% aaaiabg2da9iabgkHiTiaaiodacqGHXcqSdaGcaaqaaiaaigdacaaI<br />% 1aaaleqaaaGcbaaabaGaamyAaiaacMcacaaMc8UaaGPaVpaaL4baba<br />% GaamiEaiabg6da+iabgkHiTiaaiodacqGHRaWkdaGcaaqaaiaaigda<br />% caaI1aaaleqaaaaaaOqaaiaadMgacaWGPbGaaiykaiaaykW7caaMc8<br />% +aauIhaeaacaWG4bGaeyOpa4JaeyOeI0IaaG4maiabgkHiTmaakaaa<br />% baGaaGymaiaaiwdaaSqabaaaaaGcbaaaaaa!9ADB!<br />\[<br />\begin{gathered}<br />  8) \hfill \\<br />   \hfill \\<br />  \,\,\,\,\,\,y(y + 6) > 6 \hfill \\<br />  y^2  + 6y - 6 > 0 \hfill \\<br />   \hfill \\<br />  Sacando\,raices: \hfill \\<br />   \hfill \\<br />  \frac{{ - 6 \pm \sqrt {36 - 4( - 6 \cdot 1} )}}<br />{2} = \frac{{ - 6 \pm \sqrt {60} }}<br />{2} = \frac{{( - 3 \pm \sqrt {15} )}}<br />{{}} =  - 3 \pm \sqrt {15}  \hfill \\<br />   \hfill \\<br />  i)\,\,\boxed{x >  - 3 + \sqrt {15} } \hfill \\<br />  ii)\,\,\boxed{x >  - 3 - \sqrt {15} } \hfill \\<br />   \hfill \\ <br />\end{gathered} <br />\]<br />
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deixo
mensaje May 18 2008, 12:47 PM
Publicado: #9


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9)


TEX: <br /><br />% MathType!MTEF!2!1!+-<br />% feaafiart1ev1aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn<br />% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr<br />% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9<br />% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x<br />% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaacaWG4b<br />% WaaWbaaSqabeaacaaIYaaaaOGaeyOeI0IaaGOmaiaadIhacqGHRaWk<br />% caaIXaGaeyipaWJaaGimaaqaaiaaykW7caaMc8UaaGPaVlaaykW7ca<br />% aMc8UaaGPaVlaacIcacaWG4bGaeyOeI0IaaGymaiaacMcadaahaaWc<br />% beqaaiaaikdaaaGccqGH8aapcaaIWaaabaGaae4uaiaabMgacaqGUb<br />% GaaeiiaiaabofacaqGVbGaaeiBaiaabwhacaqGJbGaaeyAaiaabopa<br />% caqGUbGaaeiiaiaabchacaqGVbGaaeOCaiaabghacaqG1bGaaeyzai<br />% aabccacaqG0bGaae4BaiaabsgacaqGVbGaaeiiaiaab6gacaqG1bGa<br />% aeyBaiaabwgacaqGYbGaae4BaiaabccacaqGHbGaaeiBaiaabccaca<br />% qGJbGaaeyDaiaabggacaqGKbGaaeOCaiaabggacaqGKbGaae4Baiaa<br />% bccacaqGKbGaaeyzaiaabkgacaqGLbGaaeiiaiaabohacaqGLbGaae<br />% OCaiaabccacaqGTbGaaeyyaiaabMhacaqGVbGaaeOCaiaabccacaqG<br />% VbGaaeiiaiaabMgacaqGNbGaaeyDaiaabggacaqGSbGaaeiiaiaabg<br />% gacaqGGaGaae4yaiaabwgacaqGYbGaae4Baaaaaa!8E51!<br />\[<br />\begin{gathered}<br />  x^2  - 2x + 1 < 0 \hfill \\<br />  \,\,\,\,\,\,(x - 1)^2  < 0 \hfill \\<br />  {\text{Sin Soluci\'o n porque todo numero al cuadrado debe ser mayor o igual a cero}} \hfill \\ <br />\end{gathered} <br />\]<br /><br />
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alboadikto
mensaje May 18 2008, 06:28 PM
Publicado: #10


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TEX: \[<br />\begin{gathered}<br />  10.\quad 4x^2  + 12x + 9 \hfill \\<br />  \left( {x + \frac{3}<br />{2}} \right)^2  > 0 \hfill \\<br />   \hfill \\<br />  \therefore se.cumple\forall x \in \mathbb{R} - \left\{ {\frac{3}<br />{2}} \right\} \hfill \\ <br />\end{gathered} <br />\]<br />

TEX: <br />\[<br />\begin{gathered}<br />  11.x^2  - 10x + 25 \geqslant 0 \hfill \\<br />  (x - 5)^2  \geqslant 0 \hfill \\<br />  se.cumple\forall x \in \mathbb{R} \hfill \\ <br />\end{gathered} <br />\]<br />

Edit : como el 11 era corto lo deje junto con el 10 xD

Mensaje modificado por P e L a O el May 18 2008, 06:31 PM
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